I didn’t realize until just now why the selected vector always changes its fill when you change the current color. It’s picking foreground color for the “fill”, and background color for the stroke. I only noticed because I pressed a hotkey for resetting the fg/bg colors, and it changed the vector shape to black fill, white stroke. I usually avoid using the vector stuff because of stuff like this, even assigning a color is awkward (because no color picking 
). I almost never set my background color, there’s no straight forward way to adjust it (the wg color selector only sets the fg color right?).
Maybe a simple fix for the “default” color selecting would be have the “active” tab be the one the foreground color is picked from. This probably isn’t ideal since changing fg/bg color is not preserved as an undo unlike clicking on the color selector widget.
Hope someone finds this script useful.
# 2025-07-03 Written by Gemini 2.5 Pro
from krita import *
from PyQt5.QtCore import QMetaObject, Q_ARG
inst = Krita.instance()
win = inst.activeWindow()
view = win.activeView()
fg_managed_color = view.foregroundColor()
fg_qcolor = fg_managed_color.colorForCanvas(view.canvas())
print(f"Foreground color acquired: {fg_qcolor.name()}")
tool_options_docker = next(d for d in inst.dockers() if d.objectName() == 'sharedtooldocker')
fill_widget = tool_options_docker.findChild(QWidget, "KoFillConfigWidget")
btn_solid_fill = fill_widget.findChild(QToolButton, "btnSolidFill")
btn_solid_fill.click()
btn_choose_color = fill_widget.findChild(QToolButton, "btnChooseSolidColor")
action = btn_choose_color.defaultAction()
QMetaObject.invokeMethod(action,
"setCurrentColor",
Q_ARG(QColor, fg_qcolor))
action.emitColorChanged()
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